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In figure, AB is a potentiometer wire, length 10 m and resistance `2 Omega` with open the balancing length is 5.5 m. However, on closing key K the balancing length reduces to 5 m. The initial resistance of the cell `E_(1)` is A. `0.01 Omega`B. `0.1 Omega`C. `0.2 Omega`D. `1 Omega` |
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Answer» Correct Answer - B `l_(AB)=10m, R_(AB)=2 Omega, R_(AJ)=1 Omega` ` E_(1)=rho L` (When key is open) `E_(1)=rhoxx5.5 implies V_(1)=5rho` `(E-V)/(V) R=r(5.5rho-5rho)/(5rho)xx1=r(0.5)/(5)xx1=r` ` r=0.1 Omega` |
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