In Figure 1, PS = 3 cm. QS 4 et, ZPRQ=1.2 P8Q-90. PQRQ and,RQ = 9 cm. – InterviewSolution

1.

In Figure 1, PS = 3 cm. QS 4 et, ZPRQ=1.2 P8Q-90. PQRQ and,RQ = 9 cm. Evaluate tan 0.NdemJO

Answer»

In triangle QSPUsing pythagoras theoramQP^2 = QS^2 + SP^2QP^2 = 4*4 + 3*3QP^2 = 25QP = 5 cm

In triangle RPQtan theta = RQ/QP = 9/5

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