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In Fig., if AB || HF and DE || FG, then the measure of ∠FDE isA. 108°B. 80°C. 100°D. 90° |
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Answer» Given that, AB ‖ HF and CD cuts them ∠HFC = ∠FDA (Corresponding angle) ∠FDA = 28° ∠FDA + ∠FDE + ∠EDB = 180°(Linear pair) 28° + ∠FDE + 72° = 180° ∠FDE = 80° |
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