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In Fig.,△AHK is similar to △ABC.If AK = 10 cm, BC = 3.5 cm and HK = 7 cm, find AC. |
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Answer» Given ΔAHK ~ ΔABC, AK = 10 cm, BC = 3.5 cm and HK = 7 cm. We know that two triangles are similar if their corresponding sides are proportional. ⇒ \(\frac{AC}{AK}\) = \(\frac{BC}{HK}\) ⇒ \(\frac{AC}{10}\) = \(\frac{3.5}{7}\) ∴ AC = 5 cm |
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