1.

In fig acb =90 CD perpendicular AB prove cd^2=bd.ad​

Answer»

Answer:

By the theorem if the perpendicular is DRAWN to a RIGHT triangle then the triangle FORMED will be similar to each other.

Therefore triangle BCD similar to triangle ACD

therefore we can take ratio

AD/CD=CD/BD.

By cross multiplication we get

CD^2=BD.AD



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