Saved Bookmarks
| 1. |
In fig acb =90 CD perpendicular AB prove cd^2=bd.ad |
|
Answer» Answer: By the theorem if the perpendicular is DRAWN to a RIGHT triangle then the triangle FORMED will be similar to each other. Therefore triangle BCD similar to triangle ACD therefore we can take ratio AD/CD=CD/BD. By cross multiplication we get CD^2=BD.AD |
|