In fig. ABC is an isosceles triangle in which AB=AC.CP||AB and AP is the bisector of exterior ∠CAD of ΔABC. Prove that ∠PAC=∠BCA and ABCP is a parallelogram.

In fig. ABC is an isosceles triangle in which AB=AC.CP||AB and AP is t

1.	In fig. ABC is an isosceles triangle in which AB=AC.CP\|\|AB and AP is the bisector of exterior ∠CAD of ΔABC. Prove that ∠PAC=∠BCA and ABCP is a parallelogram.
Answer» In fig. ABC is an isosceles triangle in which $A B = A C . C P \| \| A B a n d A P$ is the bisector of exterior ∠CAD of ΔABC. Prove that $∠ P A C = ∠ B C A$ and $A B C P$ is a parallelogram.