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In fig., AB and CD are equal chords of a circle, with center O OM ⊥ AB and ON ⊥ CD then Prove that ∠OMN = ∠ONM |
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Answer» Given : In circle C (O, r) chord AB = chord CD and OM ⊥ AB and ON ⊥ CD To prove : ∠OMN = ∠ONM Proof : We know that equal chord of a circle are equidistant from center. Thus OM = ON ΔOMN will be an isosceles triangle. In isosceles triangle angles opposite to equal sides are equal Thus ∠OMN = ∠ONM |
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