In Fig. 8.13, find tan P-cot R.

1.	In Fig. 8.13, find tan P-cot R.
Answer» using Pythagoras law we got QR² = PR² - PQ² => QR = √ PR² - PQ² => QP = √ ( 13 )² - ( 12 )² => QP = √ 169 - 144 => QP = √25 => QP = 5 .°. tan P = QR/PQ tan P = 5/12 and Cot R = QR/PQ Cot R = 5/12 now tan P - Cot R = 5/12 - 5/12 = 0 Read more on Brainly.in - https://brainly.in/question/1345179#readmore

Answer»

using Pythagoras law we got

QR² = PR² - PQ²

=> QR = √ PR² - PQ²

=> QP = √ ( 13 )² - ( 12 )²

=> QP = √ 169 - 144

=> QP = √25

=> QP = 5

.°. tan P = QR/PQ

tan P = 5/12

and

Cot R = QR/PQ

Cot R = 5/12

now

tan P - Cot R

= 5/12 - 5/12

= 0

Read more on Brainly.in - https://brainly.in/question/1345179#readmore

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