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In Fig. 10.38, < ABC = 69", L ACB = 31°, findL BDC.Pig. 10.3731°Fig. 10.38 |
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Answer» ∠ABC = 69°, ∠ACB = 31° [Given] InΔABC∠ABC + ∠ACB+∠BAC = 180°⇒ ∠BAC = 180° - ∠ABC - ∠ACB⇒ ∠BAC = 180° -69° - 31° = 80° ∠BDC = ∠BAC ( Angle drawn from same chord) ∴ ∠BDC= 80° |
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