In equation (P+(a)/(V^(2)))=b (thetaA)/(V) pressure, V = volume, Q = absolute temp. a, b are constant. Find dimension of a

In equation (P+(a)/(V^(2)))=b (thetaA)/(V) pressure, V = volume, Q = a

1.	In equation (P+(a)/(V^(2)))=b (thetaA)/(V) pressure, V = volume, Q = absolute temp. a, b are constant. Find dimension of a
Answer» `M^(1)L^(5)T^(-2)` `M^(-1)L^(5)T^(2)` `M^(1)L^(-5)T^(-2)` `M^(1)L^(5)T^(1)` Solution :`(P+(a)/(V^(2)))= B(theta)/(V)` `[(a)/(V^(2))]=[P]` `:.[a]=[P][V]^(2)` `=(M^(1)L^(-1)T^(-2)(L^(3))^(2)` `=M^(1)L^(-1)T^(-2)xxL^(6)=M^(1)L^(5)T^(-2)`