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In each situation of column-I, some charge distributions are given with all details explained. In column -II The electrostatic potential energy and its nature is given situation in column -II. Match the proper entries from column-2 to column-1 using the codes given below the columns, Column-I A. `{:(P,Q,R,S),(1,2,4,3):}`B. `{:(P,Q,R,S),(4,1,2,3):}`C. `{:(P,Q,R,S),(1,2,3,4):}`D. `{:(P,Q,R,S),(2,4,3,1):}` |
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Answer» (A). Electrostatic potential energy `=(1)/(4piin_(0))((-Q)^(2))/(2a)=(Q^(2))/(8piin_(0)a)` (B). Electrostatic potential energy `=(1)/(4piin_(0))[((-Q)xx(-Q))/(5a//2)+((-Q)^(2))/(2(5a//2))]=(3)/(20)(Q^(2))/(piin_(0)a)` (C). Electrostatic potential energy `=(1)/(4piin_(0))(3Q^(2))/(5a)=(3)/(20)(Q^(2))/(piin_(0)a)` (D). Electrostatic potential energy `=(1)/(4piin_(0))[(3Q^(2))/(5a)+((-Q)^(2))/(2(2a))+((-Q)^(2))/(2(2a))+((-Q)xx(-Q))/(2a)]=(27Q^(2))/(80piin_(0)a)` |
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