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in each of the following, determine the value of p for which the given value is a solution of the equation. px^2+√2x-4=0, x=√2 |
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Answer» px^2+√2x-4=0 - (1) where x=√2 sub x=√2 in EQUATION (1) p(√2)^2+√2*√2-4=0 p(√2*√2)+2-4=0 p*2+2-4=0 2p-2=0 2p=2 p=2/2 p=1 |
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