In ΔSTU, the measure of ∠U=90°, TS = 41, UT = 40, and SU = 9. What

1.	In ΔSTU, the measure of ∠U=90°, TS = 41, UT = 40, and SU = 9. What is the value of the tangent of ∠S to the nearest hundredth?
Answer» Given: ΔSTU is a right angled TRIANGLE , having right angle at U . Length of side TS = 41 units Length of side UT =40 units Length of side SU = 9 units To Find : Value of tan of angle $\angle$ S = ? Solution : Since in this triangle the right angle i.e. 90° is at U, So, the side TS will be hypotenous of this triangle . We know that tangent of an angle in a right angled triangle is the ratio of length of perpendicular to length of base corresponding to that angle . So, corresponding to angle S , UT is the perpendicular and SU is the base . So, $tan \angle S = \frac{TU}{SU}$ = $\frac{40}{9}$ =4.444 Hence, the value of tangent of angle S in this triangle is 4.44

In ΔSTU, the measure of ∠U=90°, TS = 41, UT = 40, and SU = 9. What is the value of the tangent of ∠S to the nearest hundredth?

Answer»

Given:

ΔSTU is a right angled TRIANGLE , having right angle at U .

Length of side TS = 41 units

Length of side UT =40 units

Length of side SU = 9 units

To Find :

Value of tan of angle $\angle$ S = ?

Solution :

Since in this triangle the right angle i.e. 90° is at U, So, the side TS will be hypotenous of this triangle .

We know that tangent of an angle in a right angled triangle is the ratio of length of perpendicular to length of base corresponding to that angle .

So, corresponding to angle S , UT is the perpendicular and SU is the base .

So, $tan \angle S = \frac{TU}{SU}$