1.

In dimension of critical velocity v_(c) of liquid following through a tube are expressed as [eta^(x)rho^(y)r^(z)] where eta, rho and r are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively, then the values of x,y and z are given by

Answer»

1,1,1
`1,-,1-1`
`-1,-1,-1`
`-1,-1,-1,`

SOLUTION :`v_(c) prop eta^(x) rho^(y) r^(z)`
`:.v_(c)=k eta^(x) rho^(y) r^(z)` Where k is DIMENSIONLESS Writtingh dimension formula on both the side,
`M^(0)L^(1)T^(-1)=(M^(1)L^(-1)T^(-1))^(x) XX (M^(1)L^(-3)T^(0))xx (M^(0)L^(1)T^(0))^(z)`
`:. M^(0)L^(1)T^(-1)=M^(x)L^(-x)xx M^(y)L^(-3)T^(0)xx L^(z)`
`=M^(x+y)L^(-x-3y+z)T^(-x)`
COMPARING powerof M,L,T
`0=x+y "" 1=-x-3y+z "" -1=-x`
`:.1=-1-3(-1)+z :. x=1`
`:. 0=1+y "" :.1=-1+3+z`
`:.y=-1"" :. -1=z`
`:.x=1, y=-1 , z=-1`


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