In `DeltaABC, AC=BC and angleBAC=50^(@).` Find `angleBCA`. – InterviewSolution

1.	In `DeltaABC, AC=BC and angleBAC=50^(@).` Find `angleBCA`.
Answer» Given : AC=BC In a triangle, angles opposite to equal sides are equal. `:. angleABC=angleCAB=50^(@)` `angleABC+angleBCA+angleCAB=180^(@)` `50^(@)+angleBCA+50^(@)=180^(@)` `implies angleBCA=80^(@)`

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