Saved Bookmarks
| 1. |
In `Delta PQR, PD_|_ QR` and PO is the bisector of `/_ QPR`. If `/_ PQR=65^(@)` and `/_ PRQ =23(1)/(2). ^(@)` then `/_ DPO` in degrees `=`A. `20(3)/(4)`B. `20(1)/(2)`C. `20(1)/(5)`D. `20(1)/(4)` |
|
Answer» Correct Answer - a (i) Find `/_ QPR ` using `/_ QPR =180^(@)- ( /_ PQR + /_ PRQ )`. (ii) Evaluate `/_ OPQ` (iii) `/_ DPO =90^(@)- /_ POQ`. |
|