In `Delta ABC`, the bisector of `angle B` meets AC at D. A line `PQ||A – InterviewSolution

1.	In `Delta ABC`, the bisector of `angle B` meets AC at D. A line `PQ\|\|AC` meets AB,BC and BD at P,Q and R respectively. Show that `BPxxQR=BQxxPR`.
Answer» In `Delta BQP , BR` is the bisector of `angle B`. `:. (QR)/(PR)=(BQ)/(BP)` [ by angle-bisector theorem]

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