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In `Delta ABC,AC=BC` and `/_ BAC =70^(@)`. Find `/_BCA` |
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Answer» Given `AC=BC` In a triangle , angles opposite to equal sides are equal, `:. /_ABC=/_CAB=70^(@)` `/_ABC+/_BCA+/_CAB=180^(@)`. `70^(@)+/_BCA+70^(@)=180^(@)` `implies/_BCA=40^(@)`. |
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