1.

In `Delta ABC,AC=BC` and `/_ BAC =70^(@)`. Find `/_BCA`

Answer» Given `AC=BC`
In a triangle , angles opposite to equal sides are equal,
`:. /_ABC=/_CAB=70^(@)`
`/_ABC+/_BCA+/_CAB=180^(@)`.
`70^(@)+/_BCA+70^(@)=180^(@)`
`implies/_BCA=40^(@)`.


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