In damped oscillatory motion a block of mass 200g is suspended to a spring of force constant 90 N//m in a medium and damping constant is 40g//s. Find time period of oscillation

In damped oscillatory motion a block of mass 200g is suspended to a sp

1.	In damped oscillatory motion a block of mass 200g is suspended to a spring of force constant 90 N//m in a medium and damping constant is 40g//s. Find time period of oscillation
Answer» Solution :MASS ,= 200g= 0.2 kg force constant K = `90N//m` damping constant `b = 40g//s =0.04 kg//s`. `sqrt(km)= sqrt(90 xx 0.2)= sqrt(18) kg//s` Here `b lt lt sqrt(km)` TIME period `T= 2pisqrt((m)/(k))= 2pisqrt((0.2)/(90))= 0.3s`