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In ΔABC, if ∠A = 100°, AD bisects ∠A and AD ⊥ BC. Then, ∠B =(a) 50°(b) 90°(c) 40°(d) 100° |
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Answer» In ΔABC, if ∠A = 100°, AD bisects ∠A and AD ⊥ BC. Then, ∠B = (a) 50° (b) 90° (c) 40° (d) 100° |
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