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In ΔABC, ∠B = ∠C and ray AX bisects the exterior angle ∠DAC. If ∠DAX = 70°, then ∠ACB =(a) 35°(b) 90°(c) 70°(d) 55° |
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Answer» In ΔABC, ∠B = ∠C and ray AX bisects the exterior angle ∠DAC. If ∠DAX = 70°, then ∠ACB = (a) 35° (b) 90° (c) 70° (d) 55° |
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