1.

In ΔABC, AD is the perpendicular bisector of BC (See adjacent figure). Show that "ABC is an isoscele triangle in which AB = AC.

Answer»

In the attachment I have answered this problem.

Concept:

Pythagoras theorem:

In a right angle TRIANGLE, SQUARE on the hypotenuse is equal to sum of the squares on the other TWO sides.

See the attachment for DETAILED SOLUTION.



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