in compound a 1.00 gram of Nitrogen Unites with 0.57 gram of oxygen in compound B, 2.0 gram of Nitrogen combines with 2.24 gram of oxygen in compound C 3.00 gram of Nitrogen combines with 5.11 gram of oxygen this result obey the law

in compound a 1.00 gram of Nitrogen Unites with 0.57 gram of oxygen in

1.	in compound a 1.00 gram of Nitrogen Unites with 0.57 gram of oxygen in compound B, 2.0 gram of Nitrogen combines with 2.24 gram of oxygen in compound C 3.00 gram of Nitrogen combines with 5.11 gram of oxygen this result obey the law
Answer» EXPLANATION:=> Here, According to the questionCompound A : 1.00 g N + 0.57 g O₂Compound B : 2.00 g N + 2.24 g O₂Compound C : 3.00 g N + 5.11 O₂So If we fixed the amount of nitrogen (1 g) for all compound then,Compound A : 1.00 g of N Unites with 0.57 g of O₂Compound B : 2 g N ------> 2.24 O₂1 g N -------> ?= 1 * 2.24 / 2= 1.12 g O₂Compound C : 3 g N ------> 5.11 O₂1 g N -------> ?= 1 * 5.11 / 3= 1.70 g O₂=> Thus, Take in CONSIDERATION the ratio of oxygen of all three compounds for the fixed amount of Nitrogen, then we getRatio of oxygen ≈ 1 : 2 : 3=> This ratio indicates the law of multiple PROPORTION.