1.

In case of superposition of waves (atx=0), y_(1)=4sin(1026pit) and y_(2)=2sin(1014pit) (a) the frequency of resulting wave is 510Hz (b) the amplitude of resulting wave varies at frequency 3Hz (c ) the frequency of beats is 6 per second (d) the ratio of maximum to minimum intensity is 9 The correct statements are

Answer»

`a,d`
`b,d`
`a,c,d`
all

Solution :Number of beats equal to `n_(1)-n_(2)` , frequency of RESULTING wave equal to `(n_(1)+n_(2))/(2)`. RATIO of maximum and minimum INTENSITY is `((a_(1)+a_(2))/(a_(1)-a_(2)))^(2)`


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