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In Carius method of estimation of halogen. 0.45 g of an organic compound gave 0.36 g of AgBr. Find out the percentage of bromine in the compound.(Molar masses : AgBr = 188 g mol-1: Br = 80 g mol-1)(A) 34.04%(B) 40.04%(C) 36.03%(D) 38.04% |
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Answer» Correct option is (A) 34.04% Mass of organic compound = 0.45 gm Mass of AgBr obtained = 0.36 gm ∴ Moles of AgBr = \(\frac{0.36}{188}\) ∴ Mass of Bromine = \(\frac{0.36}{188}\) x 80 = 0.1532 gm ∴ % Br in compound = \(\frac{0.1532}{0.45}\) x 100 = 34.04% |
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