1.

In Carius method, `0.099 g ` organic compound gave `0.287 g AgCl.` The percentage of chlorine in the compound will beA. 28.6B. 71.7C. 35.4D. 64.2

Answer» Correct Answer - B
`%` of chorine
`=(35.5)/(143 .5) xx ("mass of AgCl")/(" mass of the compound") xx 100`
`=(35.5)/(143.5) xx (0.287)/(0.099) xx 100 xx = 71.71 %`


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