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In Carius method, `0.099 g ` organic compound gave `0.287 g AgCl.` The percentage of chlorine in the compound will beA. 28.6B. 71.7C. 35.4D. 64.2 |
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Answer» Correct Answer - B `%` of chorine `=(35.5)/(143 .5) xx ("mass of AgCl")/(" mass of the compound") xx 100` `=(35.5)/(143.5) xx (0.287)/(0.099) xx 100 xx = 71.71 %` |
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