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In biprism experiment the slit is illuminated with light of wavelength 6000A how many brigth fringes will pass a point on the screen of the path difference is altered by 0.006 cm |
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Answer» tion:Fringe width is given by β= dλD In the first case, λ 1 =6000 A ∘ =6000×10 −10 mβ 1 =6 mm=0.006 m∴0.006=6000×10 −10 dD ....(1)In the SECOND case, the DISTANCE between the SLITS and the screen is 2D ,β 2 =4 mm=0.004 m∴0.004=λ 2 × d2D ....(2)Directing equations (2) by (1) we get0.0060.004 = 2×6000×10 −10 λ 2 λ 2 = 0.0060.004×2×6000×10 −10 λ 2 = 0.00648×10 −10 λ 2 =8000×10 −10 λ 2 =8000 A ∘ . |
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