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In arrangement shown in figure, plane wavefront of monochromatic light of wavelength `lamda` is incident on identical slits `S_(1)` and `S_(2)`. There is another pair of indentical slits `S_(3)` and `S_(4)` which are having separation `Z = (lamda D)/(2d)` Point O is on the screen at the common perpendicular bisector of `S_(1)S_(2)` and `S_(3) S_(4).I_(1)` is the intensity at point O Now the board having slits `S_(3)S_(4)` is moved upward parallel to itself and perpendicular to line AO till slit `S_(4)` is on line AO and it is observed that now intensity at point O is `I_(2)` then `(I_(2))/(I_(1))` is : A. `(1)/(2)`B. 2C. 1D. 0 |
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Answer» Correct Answer - A At `S_(3)` & `S_(4)` `Delta X =(lamda)/(4) , Delta phi =(pi)/(2)` ` I_(S_(3))=I_(0)+I_(0)=I_(S_(4)),I_(1)=4(2I_(0))=8I_(0)` In final situation `I_(S_(3))=0" "I_(S_(4))=4I_(0)` `I_(2)=4I_(0)` `:. (I_(2))/(I_(1))=(1)/(2)`. |
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