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In APQR, right angle at Q, PR + QR = 25cmand PQ =5cm. Determine the values of sinPcosP and tanP. |
Answer» Solution:In triangle PQR, PQ = 5 cm PR + QR = 25 cm PR = 25 - QR By PYTHAGORAS Theorem, (PR)^2 = (PQ)^2 + (QR)^2 (25 - QR)^2 = (5)^2 + (QR)^2 625 + (QR)^2 - 50 QR = 25 + (QR)^2 625 - 25 = 50 QR 600/50 = QR QR = 12 cm PR = 25 - QR
= 25 - 12
= 13 cm sin P = P/H = PQ/PR = 5/13 COS P = B/H = QR/PR = 12/13 tan P = P/B = PQ/QR = 5/12 Hope you understand it! |
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