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In ancient time, deffernt system of units was following in which unit of mass was "`ser`", unit of length was "`gaj`" & unit of time was "`kall`" `1ser=900 gm`, `1gaj=90cm`, `1 kaal=3hr`. A ball of mass `9kg` is moving with velocity `10 m//s`. Then its momentum (`mv`) in ancient system will be `:-`A. `1.2xx10^(6)` ser `gaj^(-1)`B. `(10)^(-6)/(1.2)` ser gaj `"Kaal"^(-1)`C. `1.2xx10^(6)` ser gaj `kaal^(-1)`D. `120` ser gaj `kaal^(-1)`

Answer» Correct Answer - C
`n_(1)u_(1)=n_(2)u_(2)`
`rArr90(kg ms^(-1))=x(ser gaj kaal^(-1))`
`rArrx=90((kg)/(0.9kg)xx(m)/(0.9m)xx(3xx3600s)/(s))=1.2xx10^(6)`


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