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In anadiabaticexpansion of the airthevolumeis increased by 4%what ispereentage changein pressure?(Forair y = 1.4) |
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Answer» <P> Solution :From equation for adiabatic process,`PV^(GAMMA)="constant"` Using differentiation, we get `Pgamma V^(gamma-1)dV+dP.V^(gamma)=0` `(dP)/(P)=-gamma(dV)/(V )` Volume .V. is increased. By `4%` and `gamma=1.4` `(dP)/(P)xx100=-gamma((dV)/(V)xx100)=-1.4xx4=-5.6` PRESSURE is DECREASED. by `5.6%`. |
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