1.

In anadiabaticexpansion of the airthevolumeis increased by 4%what ispereentage changein pressure?(Forair y = 1.4)

Answer»

<P>

Solution :From equation for adiabatic process,
`PV^(GAMMA)="constant"`
Using differentiation, we get
`Pgamma V^(gamma-1)dV+dP.V^(gamma)=0`
`(dP)/(P)=-gamma(dV)/(V )`
Volume .V. is increased. By `4%` and `gamma=1.4`
`(dP)/(P)xx100=-gamma((dV)/(V)xx100)=-1.4xx4=-5.6`
PRESSURE is DECREASED. by `5.6%`.


Discussion

No Comment Found