1.

In an X-rays tube, if the electrons are accelerated through 140 KV, then anode current obtained is 30 mA. If the whole energy of electrons is converted into heat, then the rate of production of heat at anode will be :

Answer»

<P>968 CALORIE
892 calorie
1000 calorie
286 calorie.

Solution :Because `P=(Q)/(t)=(W)/(t)=VI,Q` is heat produced.
`P=140xx10^(3)xx30xx10^(-3)`
`=4200` watt=4200 Joule/sec
or `P=(4200)/(4*2)=1000` calorie.


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