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In an open, steady state system if the heat transferred is 10 J and work done by the system is 5 J, what is the change in Potential energy (neglect kinetic energy)?(a) 5 J(b) -5J(c) 15 J(d) -15 J |
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Answer» The correct answer is (a) 5 J For explanation: W + Q = ∆PE, => ∆PE = 10 – 5 = 5 J. |
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