In an obtuse-angled triangle, the obtuse angle is 3π4 and the other two angles are equal to two values of θ satisfying atanθ+bsecθ=c, where ∣∣b∣≤a2+c2, then a2−c2=kac, then the distance from origin to the line x+ky−2√5=0 is

In an obtuse-angled triangle, the obtuse angle is 3π4 and the othe

1.	In an obtuse-angled triangle, the obtuse angle is 3π4 and the other two angles are equal to two values of θ satisfying atanθ+bsecθ=c, where ∣∣b∣≤a2+c2, then a2−c2=kac, then the distance from origin to the line x+ky−2√5=0 is
Answer» In an obtuse-angled triangle, the obtuse angle is $\frac{3 π}{4}$ and the other two angles are equal to two values of $θ$ satisfying $a tan θ + b sec θ = c$ , where $∣ ∣ b ∣\leq a^{2} + c^{2}$ , then $a^{2} - c^{2} = k a c$ , then the distance from origin to the line $x + k y - 2 \sqrt{5} = 0$ is