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In an `NPN` transistor the collector current is `24 mA`. If `80%` of electrons reach collector it base current in `mA` isA. `35 mA`B. `25 mA`C. `15 mA`D. `6 mA` |
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Answer» Correct Answer - D `i_(c )=24mA=((80)/(100))i_(e)` |
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