Saved Bookmarks
| 1. |
In an LCR circuit as shown below both switches are open initially. Now switch `S_(1)` kept open. (q is charge on the capacitor and `tau = RC` is Capacitive time constant). Which of the following statement is correct? A. Work done by the battery is half of the energy dissipated in the resistorB. At `t=tau,q=CV//2`C. At `t=2tau,q=CV(1-e^(-2))`D. At `t=(tau)/(2),q=CV(1-e^(-1))` |
| Answer» Correct Answer - C | |