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In an LCR circuit as shown below both switches are open initially. Now switch `S_(1)` kept open. (q is charge on the capacitor and `tau = RC` is Capacitive time constant). Which of the following statement is correct? A. Work done by the battery is half of the energy disslpaled in the resistorB. At `t=tau, q=CV//2`C. At `t=2tau,q=CV(1-e^(-2))`D. At `t=tau/2,q=CV(1-e^(-1))` |
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Answer» Correct Answer - C `q=CV(1-e^(t//tau))` at `t=2tau` `q=CV(1-e^(-2))` |
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