1.

In an isosceles ∆ABC, if AC = BC and AB2 = 2AC2 , then ∠C = ? (a) 30°(b) 45°(c) 60°(d) 90°

Answer»

(d) 90°

Given: 

AC = BC 

AB2 = 2AC2 = AC2 + AC2 = AC2 + BC2 

Applying Pythagoras theorem, we conclude that ∆ABC is right angled at C. 

Or, ∠C = 90°



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