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In an isosceles ∆ABC, if AC = BC and AB2 = 2AC2 , then ∠C = ? (a) 30°(b) 45°(c) 60°(d) 90° |
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Answer» (d) 90° Given: AC = BC AB2 = 2AC2 = AC2 + AC2 = AC2 + BC2 Applying Pythagoras theorem, we conclude that ∆ABC is right angled at C. Or, ∠C = 90° |
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