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In an ideal transformer, number of turns in primary and secondary are 200 and 1000 respectively. If the power input to the primary is 10 kW at 200 V, calculate (i) output voltage (ii) primary current. |
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Answer» Here, `n_(P) = 200, n_(s) = 1000`, `P_(i) = 10 kW = 10000 W, E_(P) = 200 V` `E_(s) = ?, I_(P) = ?` As `(E_(s))/(E_(P)) = (n_(s))/(n_(P)) = (1000)/(200) = 5` Also, `E_(P) I_(P) = P_(i) = 1000`, `I_(P) = (10000)/(E_(P)) = (10000)/(200) = 50 A` |
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