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In an experiment to measure the internal resistance of a cell by a potentiometer, it is found that the balance point is at a length of `2 m` when the cell is shunted by a `5 Omega` resistance and is at a length of `3 m` when the cell is shunted by a `10 Omega` resistance, the internal resistance of the cell is thenA. `12 Omega`B. `8 Omega`C. `16 Omega`D. `1 Omega` |
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Answer» Correct Answer - B As, `((1-2)/(2))4=((1-3)/(3))8 implies l=6` Therefore, `r=((1-2)/(2))4=8 Omega` |
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