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In an experiment, to determine the percentage purity of the hydrochloric acid, 25cm3 of the acid solution made by dissolving 25.5g of impure acid in a liter of solution was found to neutralize 25cm3 of 0.4M NaOH solution. Calculate a. Concentration of the acid in (i) g/dm3 (ii) mol/dm3 b. percentage purity of the acid c. percentage impurity of the acid |
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Answer» tion:V1S1=V2S2 Here, V1= 25 CM3, V2=25 cm3, S2= 0.4 MS1 = (25×0.4) /25 M =0.4 MStrength of the acid is 0.4 MOL / dm3m = N×M Here, n= 0.4 mol / dm3, M= 36.46 g/mol = 0.4×36.46 g / dm3 =14.584 g / dm3 |
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