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In an experiment , the following observations were recorded: `L = 2.820 m , M = 3.00 kg , l = 0.087 cm , diameter , D = 0.041 cm`. Taking ` g = 9.81 m s^(-2)` and using the formula , `Y = ( 4MgL)/( pi D^(2) l)` , find the maximum permissible error in `Y`.A. `7.96%`B. `4.56%`C. `6.50%`D. `8.42%` |
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Answer» Correct Answer - C `Y=(4MgL)/(piD^2l)` so maximum permissible error in Y `(triangleY)/(Y)xx100=((triangleM)/(M)+(triangleg)/(g)+(triangleL)/(L)+(2triangleD)/(D)+(trianglel)/(l))xx100` `=((1)/(300)+(1)/(981)+(1)/(2820)+2xx(1)/(41)+(1)/(87))xx100` `=0.065xx100=6.5%` |
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