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In an experiment four quantities a,b,c and d are measure with percentage error `1% , 2% , 3%`,and `4%` respectively quantity is P is calculate as follow `P = (a^(3)b^(2))/(cd) %` error in `P` isA. 0.04B. 0.14C. 0.1D. 0.07 |
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Answer» `P=(a^(3)b^(2))/(cd)rArr(Deltap)/(P)=+-(3(Delta)/(a)+2(Deltab)/(b)+(Deltac)/(c)+(Deltad)/(d))` `=+-(3xx1+2xx2+3+4)` `=+-14%` |
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