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In an experiment for determination of refractive index of glass of a prism by i -delta ,plot, it was found that a ray incident at angle 35^(@) , suffers a deviation of 40^(@) and that it emerges an angle 79^(@) . In that case which of the following is closest to the maximum possible value of the refractive index? |
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Answer» 1.5 4 = 114 - A , A = 114 - 40 = 74 = `r_(1)+r_(2)` From this we get ` mu=1.5`, `delta_(min)lt40^(@)` sin (((70+40)/2)/sin 37), `:.mu_(max)=1.44` 
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