1.

in an experiment 4g of M2Ox OXIDE WAS reducatomic mass ed to 2.8% of the metal. if the atomic mass of the metal is 56g/mol , the no. of oxygen atom in the oxide is...?

Answer»

Answer:

1 Mol M2Ox = (2 X 56 + 16 x) GM

Now ,(2 x 56 + 16 x) of oxide = 112 gm METAL

 4 gm of oxide = 112 x 4/112 + 16 x gm metal

But 112 x 4/112 + 16 x = 2.8(given) :.

 x = 3

me again



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