Saved Bookmarks
| 1. |
in an experiment 4g of M2Ox OXIDE WAS reducatomic mass ed to 2.8% of the metal. if the atomic mass of the metal is 56g/mol , the no. of oxygen atom in the oxide is...? |
|
Answer» Answer: 1 Mol M2Ox = (2 X 56 + 16 x) GM Now ,(2 x 56 + 16 x) of oxide = 112 gm METAL 4 gm of oxide = 112 x 4/112 + 16 x gm metal But 112 x 4/112 + 16 x = 2.8(given) :. x = 3 me again |
|