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| 1. |
In an equilateral triangle ABC of side 10cm, the side BC Is trisected at D. Then the length (in cm) of AD is1). $3\sqrt{7}$2). $7\sqrt{3}$3). $\frac{10\sqrt{7}}{3}$4). $\frac{7\sqrt{10}}{3}$ |
| Answer» OPTION 3 : - $7\sqrt{3}$ | |