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In an electrical circuit two resistors of 2 ohm and 4 ohm respectively are connected in parallel to a 6 Volt battery. The heat dissipated by the 4 ohm resistor in 5 seconds will be? |
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Answer» H = vit so we have to find i I=v/r l=6/4 l= 3/2 apply to FORMULA h=vit h=6×3/2×5 h=45joules PLEASE mark me a brainlist please |
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