In an attempt to prepare propane by Wurtz reaction I mole of methyl bromide and I mole of ethyl bromide are treated with sodium. Assuming equal probability for all possible reaction. How many g of propane will be obtained?

In an attempt to prepare propane by Wurtz reaction I mole of methyl br

1.	In an attempt to prepare propane by Wurtz reaction I mole of methyl bromide and I mole of ethyl bromide are treated with sodium. Assuming equal probability for all possible reaction. How many g of propane will be obtained?
Answer» re assuming the equal probabilities of a reaction : 1 mol of methyl BROMIDE and ethyl bromide will PRODUCE CH3CH2CH3 (propane). The reaction of both reactants in the PRESENCE of sodium is GIVEN below : CH3Br + CH3CH2Br + 2 Na----------> CH3CH2CH3 + CH3CH2CH2CH3 + 2NaBr 1 mol of propane = molar mass = 44.0 g Mass of CH3CH2CH3 = 44 / 3 = 14.67 g