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In an AP:Given al,-37, d # 3, find a and S12 |
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Answer» given a12=37 d=3 a+11d=37a+11×3=37a+33=37a=37-33a=4 S12=(n/2)(a+a12)S12=12/2×(4+37)S12=6×41S12=246 |
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