1.

In an AP:Given al,-37, d # 3, find a and S12

Answer»

given a12=37 d=3

a+11d=37a+11×3=37a+33=37a=37-33a=4

S12=(n/2)(a+a12)S12=12/2×(4+37)S12=6×41S12=246



Discussion

No Comment Found