1.

in an ammeter 0.2% of main current passes through tha galvanometer. if resistance of galvanometer is G the resistance of ammeter will be.......✌️​

Answer»

The RESISTANCE of ammeter will be 1/499 G.

Explanation:

For ammeter:

0.0002 l x G = 0.9981 x rg

rg = 0.002 / 0.998 G

That is

rg = 0.002004

   = 1/499 G

Hence the resistance of ammeter will be 1/499 G.

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