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in an ammeter 0.2% of main current passes through tha galvanometer. if resistance of galvanometer is G the resistance of ammeter will be.......✌️ |
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Answer» The RESISTANCE of ammeter will be 1/499 G. Explanation: For ammeter: 0.0002 l x G = 0.9981 x rg rg = 0.002 / 0.998 G That is rg = 0.002004 = 1/499 G Hence the resistance of ammeter will be 1/499 G. please CHOOSE as BRAINLIEST |
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